Let $X \in \text{Random}[0, \infty]$ be a D5452: Random unsigned real number.
Let $\lambda > 0$ be a D993: Real number.

Then \begin{equation} \mathbb{P}(X \geq \lambda) \leq \frac{1}{\lambda} \mathbb{E}(X) \end{equation}

Let $P = (\Omega, \mathcal{F}, \mathbb{P})$ be a D1159: Probability space such that

(i)	$X : \Omega \to [0, \infty]$ is a D4381: Random basic number on $P$

Let $\lambda > 0$ be a D993: Real number.

Then \begin{equation} \mathbb{P}(X \geq \lambda) \leq \frac{1}{\lambda} \mathbb{E}_{\mathbb{P}} (X) \end{equation}

Let $P = (\Omega, \mathcal{F}, \mathbb{P})$ be a D1159: Probability space such that

(i)	$X : \Omega \to [0, \infty]$ is a D4381: Random basic number on $P$

Let $\lambda > 0$ be a D993: Real number.

Then \begin{equation} \mathbb{P}(X \geq \lambda) \leq \frac{1}{\lambda} \int_{\Omega} X(\omega) \, \mathbb{P}(d \omega) \end{equation}