ThmDex – An index of mathematical definitions, results, and conjectures.
Result R708 on D1107: Metric space
Reverse triangle inequality for metric
Formulation 0
Let $M = (X, d)$ be a D1107: Metric space.
Then \begin{equation} \forall \, x, y, z \in X : |d(x, z) - d(y, z)| \leq d(x, y) \end{equation}
Proofs
Proof 0
Let $M = (X, d)$ be a D1107: Metric space.
If $X$ is empty, the claim holds vacuously so assume that $X$ is nonempty and fix $x, y, z \in X$. By the triangle inequality metric axiom, we have $d(x, z) \leq d(x, y) + d(y, z)$. Subtracting $d(y, z)$ from both sides, this gives \begin{equation} d(x, z) - d(y, z) \leq d(x, y) \end{equation} Next, again by triangle inequality, we have $d(y, z) \leq d(y, x) + d(x, z)$. Subtracting $d(x, z)$ from both sides and applying symmetry in $d(y, x) = d(x, y)$, this gives \begin{equation} - (d(x, z) - d(y, z)) = d(y, z) - d(x, z) \leq d(x, y) \end{equation} Thus, by the definition of the D412: Absolute value function, we have the lower bound \begin{equation} |d(x, z) - d(y, z)| \leq d(x, y) \end{equation} $\square$