ThmDex – An index of mathematical definitions, results, and conjectures.
Change of base formula for logarithm function
Formulation 0
Let $\log_a$ be the D866: Standard real logarithm function in base $a \in (0, \infty) \setminus \{ 1 \}$.
Let $b \in (0, \infty) \setminus \{ 1 \}$ be a D5407: Positive real number.
Then \begin{equation} \log_a x = \frac{\log_b x}{\log_b a} \end{equation}
Proofs
Proof 0
Let $\log_a$ be the D866: Standard real logarithm function in base $a \in (0, \infty) \setminus \{ 1 \}$.
Let $b \in (0, \infty) \setminus \{ 1 \}$ be a D5407: Positive real number.
Directly from the definitions, we have \begin{equation} \frac{\log_b x}{\log_b a} = \frac{\frac{\log_e x}{\log_e b}}{\frac{\log_e a}{\log_e b}} = \frac{\log_e x}{\log_e a} = \log_a x \end{equation} $\square$