ThmDex – An index of mathematical definitions, results, and conjectures.
Result R1177 on D201: Measurable map
Constant map is always measurable
Formulation 0
Let $M_X = (X, \mathcal{F}_X)$ and $M_Y = (Y, \mathcal{F}_Y)$ each be a D1108: Measurable space such that
(i) $f : X \to Y$ is a D1519: Constant map from $X$ to $Y$
Then $f$ is a D201: Measurable map from $M_X$ to $M_Y$.
Proofs
Proof 0
Let $M_X = (X, \mathcal{F}_X)$ and $M_Y = (Y, \mathcal{F}_Y)$ each be a D1108: Measurable space such that
(i) $f : X \to Y$ is a D1519: Constant map from $X$ to $Y$
Let $\sigma_{\text{pullback}} \langle f \rangle$ be the D1730: Pullback sigma-algebra on $X$ under $f$ with respect to $M_Y$. Result R2548: Constant map pulls back a bottom sigma-algebra shows that $\sigma_{\text{pullback}} \langle f \rangle = \{ \emptyset, X \}$ and result R4651: Bottom sigma-algebra is always a subsigma-algebra shows that \begin{equation} \sigma_{\text{pullback}} \langle f \rangle = \{ \emptyset, X \} \subseteq \mathcal{F}_X \end{equation} This establishes the result. $\square$